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oakpacific
waxwing: can you sign a piece of encrypted RSA ciphertext with the same key? Wouldn't it be like decrypting it?
oh, no
ciphertext is first hashed, then signed
so that in itself is ok then?
waxwing
key role reversal right oakpacific ?
oh sorry i got you now
yeah i can't say for sure, but why not use DSA?
i'm guessing you mean 'does giving a signature endanger the secrecy of the original message'
oakpacific
waxwing: DSA is notorious, isn't it?
but i am purely investigating out of theoretical interest here
there is no harm using two separate keys after all
waxwing
s/DSA/whatever the currently accepted signature system is/
:)
oakpacific
waxwing: there is none other than RSA tbh
waxwing
other than RSA?
or DSA?
oakpacific
yes
depends on
what you meant by 'accepted'
asking djb about his opinion on ECDSA/DSA and you would regret you ever got into cryptography
:)
waxwing
but i don't know what you're investigating anyway. i guess you're right that people always use different keys for the two operations, but it's possible to use the same i guess
made me giving up my handrolled, handbaked crypto :)
waxwing
isn't that the one you linked to before?
oakpacific
i think i linked to axolotol
rather than this one
or is it this one
waxwing
it was like, what you linked was a reference to that
oakpacific
never read past the original otr part though
waxwing: wanna know what was my handbaked pastry?
:)
waxwing
you'd be wasting your time, i don't understand otr yet
oakpacific
don't worry, i assure you will want to slap my face :)
so each time, both A and B, need to create a ephemeral secret g^(ab) mod p, but it's well known that DH doesn't do authentication on its own
so basically the idea was for each two parties in one communication, one party creates a prime modulus p specifically for them, and sign it and pass to the other party, so if both people don't reveal it, they can be sure next time when they receive a g^a mod p, if it's authentic :)
also p has to be passed with something like RSA
waxwing
so does the RSA pubkey have to be authenticated then?