#django

elmcrest: you could just store all terms in a list and reduce(and_, or_list) them at the end

dAnjou : Ok thanks for your help. I just found this : https://github.com/zlorf/django-synchro it's exactly what I want to do

elmcrest: https://gist.github.com/jtiai/ebebc4a3c1dec2fc1400 oops, that was meant for you :)

Silvering: but as the other guys said, it depends on what your app should do offline. maybe a simple hack is enough.

moritz_s: and is the default action for filter/exclude...

moritz_s: it's OR you tend to need to apply

hi folks

jtiai: ok, thx - I try to get my head around this :)

I want to retrieve a sublist of objects according to their number

jtiai: in deed seems to be the same or what I want to get in the end :)

objects are clustered, and I want to retrieve the biggest cluster

Dr_ST: what do you mean "their number"?

how much they are

Dr_ST: clustered how?

dAnjou : The offline app will display text content fetched from the online database

DockingLigand.objects.filter(docking=self).annotate(cluster_count=Count('cluster')).order_by('-cluster_count')

Silvering: if i understood you correctly, it's not doing what you want

Dr_ST: so, you mean according to the value of a specific field

yep

Dr_ST: that look sright

not the value, but how much there are with the same value in a field

Silvering: with this app you'd have to install your django app on the same machine that's displaying the website

dAnjou : you are right I read too fast...

how many there are...

ok

FunkyBob: I'm aware of that, but since elmcrest is using plain Q objects, you have to use | or & explicitely

Dr_ST: so what's the problem?

moritz_s: yes and no

I don't get the good info

FunkyBob: What do you mean?

or not reading it the proper way

moritz_s: you can start with a Q(), then |= each successive one for OR cases

moritz_s: but if you need to AND then, you can pas them as positional arguments to filter()

Dr_ST: "the good info" being?

how much I have objects in each cluster

it seems the above query does not filter by the count

FunkyBob: yeah, you're right

moritz_s: but reduce(and_, list_of_qs) should work as well

for instance using DockingLigand.objects.filter(docking=self).annotate(cluster_count=Count('cluster')).order_by('-cluster_count')[0] should return 10 since this "cluster field" has the most important number of objects

Dr_ST: each object will have clister_count as a property

FunkyBob: so positional args to filter() and ANDed so to speak?

moritz_s: yes

but it returns 9 ...

elmcrest: right, just like their keyword args are

Dr_ST: .... and?

well 9 is not 10 :-)

Dr_ST: look, if you want hlep, you need to explain stuff in detail , instead of assuming we can read your mind/screen

ok, back to the point

FunkyBob Ok good to know... Maybe moritz_s suggestion is a little more explicite but anyway

I have 100 objects (or more) which can have a "cluster" field in common

some are in cluster 1, some in cluster 2, some in cluster 3, etc

I want to now which cluster is the most populated

ah, well

but just the cluster and its size?

from the data I know this is cluster 2 which has 10 members

yep

The object is more complex, but I want to sort according to cluster size, to keep only the most populated cluster

DockingLigand.objects.filter(docking=self).values('cluster').annotate(count=Count('cluster'))

Hello. I can't make auth with facebook through python-social-auth - it causes error 404 with "Backend not found".

now you get a queryset that yields dicts with two values: cluster and count

dAnjou: For my mind, the best solution is from the local app, to fetch a json file, store is locally and update the database. This is possible I think so

But I already add 'social.backends.facebook.FacebookOAuth2' to my AUTHORIZATION_BACKENDS.

FunkyBob, haaaaaaaaa, the queryset returns a dict ... thanks :-)

*AUTHENTIFICATION

Dr_ST: values() querysets do

Dr_ST: actually you probably wanted aggregate()

this is what was missing, I was trying to get the object alone

ok, thanks, gtg eating, I'll experience just after lunch :-)

DockingLigand.objects.filter(..).aggregate(count=Count('cluster'))

should yield a dict of cluster:count

Silvering: It's possible but not trivial to handle conflicts and such. Why are you needing this "offline" mode?

jtiai : Because this app will works like a "show" without internet connection. After the show the app could be updated

django newbie, need help, difficulty in sessions, after logging in i am trying to check if session has an entry of the user, by the request.user but apparently session is not getting the user entry in it. https://dpaste.de/4Jfi .

Problem solved, my my.cnf didn't have good enough permissions

print request.user to no avail, shouldnt their be some sort of output indicating the user

ameenkhan07: request.user is only set after login()

I have a CharField with choices but I'd like to display each choice individually in a form based on the model. I currently have this: https://dpaste.de/uzYG but it keeps displaying all the languages in one select. Could anyone tell me what I'm doing wrong?

Boogymanx: Which widget you would like to use?

moritz_s: done the login, and found out the fault. But when trying with android http request to the django backend, session is not being maintained

jtiai: a select widget is okay for the knowledge_level for the time being, I'd just like the languages themselves displayed as text instead of another select

ameenkhan07: the android http request probably doesn't store the cookies

Boogymanx: That mechanism you show can only handle one single language. You probably would like to figure out to handle several (prefixed) forms to your view.

moritz_s: ohh, so what should i do in that case?

is that something to be done on the android part or the backend django part?

ameenkhan07: Django can't know who you are if you don't send it the cookies back.

moritz_s: could you explain a little more?

jtiai : I think I found an easier solution. I don't need a django app locally. If I create a simple website which fetch text content from a json file downloaded when internet is available, I'm happy! The json file is created by the django app hosted by heroku! Done!

Boogymanx: I mean that what you're trying to do doesn't work that way. You need one form for each language, and in a view you need to construct and loop over each language form. Nothing magical.

jtiai: Is there no way to do that programmatically? Loop over all languages in the model and create the forms that way?

jtiai: Or is my model wrong in this case?

ameenkhan07: I won't explain how cookies work, you can google that, but to answer your questions: you have to do something on the android part

Boogymanx: No. most probably your view and modelform is wrong.

Boogymanx: And thus your template.

jtiai: The view is the view you and FunkyBob helped me with yesterday, only with language_form=LanguageForm() appended and adding language_form to the render()

moritz_s: AWESOME, all needed to know, thanks :)

Boogymanx: Well if you add _one_ form you can handle only _one_ language and it's level.

Boogymanx: Can you dpaste your view again.

jtiai: https://dpaste.de/1V1J

(I only just started working on this, which is why I haven't added a is_valid and save() for it yet, want to get it displaying correctly before I do that)

Am I still connected? <_<

YES

oops

Silvering: are you aware that you can generate JSON on the fly with django from, let's say, a database query result

?

Boogymanx: https://dpaste.de/zkMj#L29,30,56,60,61,62 something like that (highlighted added/changed stuff)

Awesome, thanks jtiai!

Boogymanx: You owe me a beer... :)

How can I pay you?

I'm from Belgium so I might be able to send you one through mail :p

if you have any favourites here :)

Well I already get paid. :)

But I know that in Belgium are really good abbey beers.

And trappists.

Oh hell yes

trappists are my favourite kind of beer

I love me some Rochefort :D

You can get absolutely wasted on three or four of those

dAnjou : Yes I know this part is ready. Is working on heroku and Json files are created for each item

jtiai: pm me your details and I'll see if I can mail you a selection of trappists ^^