#django

So...I have a user model with two fields that specify that their default values are the result of a function. No big deal.

I have a management command which does NOTHING with that same function, and yet I am seeing it called, simply by having the default value present.

It is worth noting that the fields with the default values are a UserProfile field, and registered as such.

Any reason why calling ./manage.py myfunc would cause this function to be called in the UserProfile field?

Anyway to make it not do that? It's a little confusing.

It should only print "hi there"...no idea why the output of the other function (that is simply used to provide default value) is being shown.

Shorter version of my question: does calling a command created for manage.py instantiate a User?

no

your code is wrong

but it has nothing to do with django

ok

look at your class defintion

the fields in which you're setting a default

what are you setting the default *to*?

part of the output of the function.

the function returns a pair...something like (5,6)

one field gets the first value, the second the other.

What I don't get is why the management command, which right now only prints a message, would instantiate User (or UserProfile)

okay, so now you've set the default for every single instance to (5,6)

you sure that's what you want?

Not for every instance...just new ones, right?

the function will increment the values to other pairs that are not used.

nope. it only ever gets run once, so it's going to be the default for every instance

really?

sure. try it with a simple example

class A:

hmm, okay, not going to write code in the channel :)

so the function only gets evaluated at start time? Once. Not at instantiation?

Interesting.

correct, that's how python works

I was about to say I've done something similar before...but thinking about it...I had the function get called in a form, not the model.

you got it :)

but again, nothing to do with django. you *can* do what you want in a model

you just have to pass a *function* instead of the the *output* from a function

for example, default=lambda: get_next_vpn_ip_pair()[1]

heh...so, take away the two fields thing... could I have also just said default=get_next_vpn_ip_pair, w/o the parens. Or is lambda req'd to do this?

no, just passing the function would be enough

The More You Know(tm)

lemme go try!

Lambda isn't required for anything in Python.

Though...so I was seeing that function called, since django does some initialization when running the command right? Including instantiating a User of some kind?

it's not done at instanciation

it's done when building the class

that's why you can do things like generate classes on the fly

mattmcc: you around

More or less.

jfw, SmileyChris...dead on! Thank you for the assist!

hey there I need some help with this problem

see this: http://dpaste.org/Zp6wS/#L

no prob! cheers

hi, I have a big template that makes heavy uses of the regroup template tag. I suspect this is why it is so slow. Is there any alternative to it? (i'm thinking on the queryset/database level)

hey, can anyone help with this? http://dpaste.org/Zp6wS/#L trying to get the view to look like what I describe at the bottom

aleray: do you have a site with big template ?

jasongonzales: you haven't said what the problem is

codeme, not sur to understand your question... My english is kind of broken. I meant a large template

aleray: move your logic to your view or model

jfw, I could use itertool or something like this but will it be faster?

i couldn't possibly say. it depends on many things

I have many regroup tag nested...

that's bad

even if not for speed (which it's probably pretty bad for) that's going to be a pain to maintain

anytime you find yourself doing anything complicated or nesting more than a level or two deep, move the logic to your view or model

jfw, here is a snippet http://dpaste.com/1077213/

(includes also use regroup tags :()

jfw, an other one http://dpaste.com/1077215/ which should give you a pretty good overview of the whole

or more specifically: how can I make less expense such a statement? `{% regroup o.foo|dictsort:"o.foo" by o.foo as oo %}`

is it possible to use startproject —template and specify that files *without* an extension should be rendered? by default only .py files are rendered... i can add additional extensions with -e but how do i add the lack of an extension? (Makefile in docs dir, created by sphinx-quickstart) ?

__machine: That's probably bug report worthy, because I bet it's not supported..

And it obviously should be, since we unix people aren't supposed to care about file extensions.

thanks i will open a ticket

looks like it's already done... with a —name argument... yay...

jfw: any direction to suggest?

when you do loaddata fixtures/initial_fixtures.json

does it actually overwrite the database?

or does it add new entries if it's an existing db?

hmm looks like it wipes out the db, because there's no duplicate entries while there should have been after i ran loaddate